y^2+11y+25=13

Solution for y^2+11y+25=13 equation:

y^2+11y+25=13

We move all terms to the left:

y^2+11y+25-(13)=0

We add all the numbers together, and all the variables

y^2+11y+12=0

a = 1; b = 11; c = +12;
Δ = b2-4ac
Δ = 112-4·1·12
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{73}}{2*1}=\frac{-11-\sqrt{73}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{73}}{2*1}=\frac{-11+\sqrt{73}}{2}
$